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The three vessels are X, Y, and Z. The ratio of ingredients A and B in vessel X is 6 : 5, the ratio of ingredients B and C in vessel Y is 7 : 4 and the ratio of ingredients C and A to vessel Z is 3: 8, the mixture of the three vessels is mixed in a ratio of 2 : 5 : 8  and placed in a new vessel P, then what is the percentage of ingredient B in the new vessel? (near to two decimal points)

The three vessels are X, Y, and Z. The ratio of ingredients A and B in vessel X is 6 : 5, the ratio of ingredients B and C in vessel Y is 7 : 4 and the ratio of ingredients C and A to vessel Z is 3: 8, the mixture of the three vessels is mixed in a ratio of 2 : 5 : 8  and placed in a new vessel P, then what is the percentage of ingredient B in the new vessel? (near to two decimal points) Correct Answer 27.27%

Given:

In-vessel X, The ratio of A and B = 6 : 5

In-vessel Y, The ratio of B and C = 7 : 4

In-vessel Z, The ratio of C and A = 3 : 8

The ratio of mixture of three vessels = 2 : 5 : 8

Calculation:

By adding, the ratio of every vessel the quantity is a multiple of 11.

Therefore, The new mixture quantity should be 22 : 55 : 88

According to the question

The quantity of vessel X having A and B = 12 : 10

The quantity of vessel Y having B and C = 35 : 20

and, the quantity of vessel Z having C and A = 24 : 64

In-vessel P,

The ratio of A, B and C = ( 12 + 64 ) : ( 10 + 35 ) : ( 20 + 24 )

⇒ 76 : 45 : 44

Required% = 45 × 100/165

⇒ 27.27%

∴ The percentage of ingredient B in the vessel is 27.27%.

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