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There are two vessels A and B. Vessel A is containing 60L of Pure milk and vessel B is containing 28L of pure water. From vessel A, 8L of milk is taken out and poured into vessel B. Then, 6L of mixture (milk and water) is taken out from vessel B and poured into vessel A. What is the ratio of the quantity milk in vessel A to the quantity of pure water in vessel B?

There are two vessels A and B. Vessel A is containing 60L of Pure milk and vessel B is containing 28L of pure water. From vessel A, 8L of milk is taken out and poured into vessel B. Then, 6L of mixture (milk and water) is taken out from vessel B and poured into vessel A. What is the ratio of the quantity milk in vessel A to the quantity of pure water in vessel B? Correct Answer 16 ∶ 7

GIVEN :

There are two vessels A and B. Vessel A is containing 60L of Pure milk and vessel B is containing 28L of pure water.

From vessel A, 8L of milk is taken out and poured into vessel B. Then, 6L of mixture (milk and water) is taken out from vessel B and poured into vessel A.

 

CALCULATION :

Initial quantity of milk in vessel A = 60L

Initial quantity of water in vessel B = 28L

Now, 8L milk of is poured to vessel B

Quantity of milk left in vessel A = 60 - 8 = 52 L

Quantity of milk in vessel B = 8L

Quantity of water in vessel B = 28L

(Milk ∶ water) in vessel B = 8 ∶ 28 = 2 ∶ 7

Now, 6L of mixture (milk and water) is taken out from vessel B and poured into vessel A.

Quantity of milk in 6L = 6 × 2/9 = 4/3

Quantity of water in 6L = 6 × 7/9 = 14/3

Now, Quantity of milk in vessel A = 52 + 4/3 = 160/3

Quantity of water in vessel B = 28 - 14/3 = 70/3

∴ Required Ratio = 160/3 ∶ 70/3 = 16 ∶ 7

 

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