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Two vessels A and B contain a mixture of acid and Water. In vessel A the ratio of acid and water is 2 ∶ 1 and in vessel B the ratio is 5 ∶ 1.Mixture from these two vessels are filled in another 42 litre vessel to contain a mixture of acid and water in the ratio of 5 ∶ 2. How much mixture is taken from vessel A?

Two vessels A and B contain a mixture of acid and Water. In vessel A the ratio of acid and water is 2 ∶ 1 and in vessel B the ratio is 5 ∶ 1.Mixture from these two vessels are filled in another 42 litre vessel to contain a mixture of acid and water in the ratio of 5 ∶ 2. How much mixture is taken from vessel A? Correct Answer 30 litres

Given:

In vessel A the ratio of acid and water = 2 ∶ 1

In vessel B the ratio of acid and water = 5 ∶ 1

In another 42 litre vessel contains a new mixture of acid and water in the ratio of 5 ∶ 2

Concept:

Calculation:

Let, x litre mixture is taken from vessel A

(42 – x) litre mixture is taken from vessel B

According to the question,

⇒ (2x/3) + (5/6) × (42 – x) = 42 × (5/7)

⇒ (2x/3) + 35 – (5x/6) = 30

⇒ (5x/6) – (2x/3) = 5

⇒ 5x – 4x = 30

⇒ x = 30

∴ 30 litre mixture is taken from vessel A

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