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A vessel of capacity 2 litre has 25% alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. what is the new concentration of mixture ?

A vessel of capacity 2 litre has 25% alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. what is the new concentration of mixture ? Correct Answer 29%

Amount of alcohol in first vessel,= 25% of 2 litre = 0.25 × 2 = 0.5 litreAmount of alcohol in second vessel,= 40% of 6 litre = 0.4 × 6 = 2.4 litreTotal amount of alcohol out of 10 litres of mixture is0.5 + 2.4 = 2.9 litreThus, Concentration of the mixture is,$$\frac{{2.9 \times 100}}{{10}}$$= 29%

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