There are three vessels A, B and C having milk to water ratio as 3 : 5, 1 : 3 and 7 : y. After adding mixture of vessel B to A, the milk to water ratio becomes 1 : 2 in A. Now 60% of mixture is taken out from vessel A and mixture of vessel C is mixed with remaining mixture of vessel A which results in a final milk to water ratio of 3 : 4. Find the value of y given that volume of B is 20 litres and volume of C is (7 + y) lires
There are three vessels A, B and C having milk to water ratio as 3 : 5, 1 : 3 and 7 : y. After adding mixture of vessel B to A, the milk to water ratio becomes 1 : 2 in A. Now 60% of mixture is taken out from vessel A and mixture of vessel C is mixed with remaining mixture of vessel A which results in a final milk to water ratio of 3 : 4. Find the value of y given that volume of B is 20 litres and volume of C is (7 + y) lires Correct Answer 4
Given that:
In vessel A , milk and water ratio = 3 : 5 ,
In vessel B, milk and water ratio = 1 : 3
In vessel C milk and water ratio = 7 : y
Calculation:
According to question,
Volume of B is 20 litres
Milk in vessel B = 20 × 1/4 = 5 litres
Water in vessel B = 20 × 3/4 = 15 litres
When this is added to vessel A
⇒ (3y + 5)/(5y + 15) = 1/2
⇒ 6y + 10 = 5y + 15
⇒ y = 5 litres
Hence, milk in vessel A = 3y + 5 = 3 × 5 + 5 = 20 litres
Water in vessel A = 5y + 15 = 5 × 5 + 15 = 40 litres
60% of mixture of A = (40 + 20) × 60/100 = 36 litres
Remaining mixture = 24 litres
Milk remaining = 8 litres
Water remaining = 16 litres
After adding the content of vessel C.
⇒(8 + 7)/(16 + y) = 3/4
⇒ 60 = 48 + 3y
⇒ y = 4
The value of y = 4