If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s , then the frequency for the second note is

Question

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s , then the frequency for the second note is

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s , then the frequency for the second note is
A. `4xx330/4Hz`
B. `3xx330/4Hz`
C. `2xx330/4Hz`
D. `2xx4/330Hz`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`n_c = (v)/(4l) = (330)/(4xx1) = 330/4`
`n_1 = 3n_c = (3xx330)/(4)`

6 views Answered 2023-02-05 15:29