An open pipe resonates to a fundamental frequency 300 Hz and closed pipe to a fundamental frequency 150Hz. If they are joined to form a longer closed tube, then the fundamental frequency of resonance will be
A. 72Hz
B. 75Hz
C. 45Hz
D. 47Hz

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1 Answers

Correct Answer - B
`n=(n_1n_2)/(2n_2n_1)=(300xx150)/(300+300) = (300xx150)/(600) = 75`

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