An open organ pipe of length is 50 cm, if the velocity of sound in air is 320m/s , then the frequency of its fundamental note will be

Question

An open organ pipe of length is 50 cm, if the velocity of sound in air is 320m/s , then the frequency of its fundamental note will be

An open organ pipe of length is 50 cm, if the velocity of sound in air is 320m/s , then the frequency of its fundamental note will be
A. 160Hz
B. 480Hz
C. 320Hz
D. 640Hz

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`n=(v)/(2l) = (320)/(50xx2xx10^(-2))-320Hz`

4 views Answered 2023-02-05 15:29