Mixture A and Mixture B contain consist of 40 liters and 60 liters of mixtures of liquids X and Y in different proportions. Quantity of liquid X in mixture A is 10 liter less than the quantity of liquid X in mixture B. The total quantity of liquid Y in both the mixtures is 40 liters. If 30% of liquid is taken from mixture A and put into mixture B, then what will be the ratio of liquid X to liquid Y in mixture B?

Mixture A and Mixture B contain consist of 40 liters and 60 liters of mixtures of liquids X and Y in different proportions. Quantity of liquid X in mixture A is 10 liter less than the quantity of liquid X in mixture B. The total quantity of liquid Y in both the mixtures is 40 liters. If 30% of liquid is taken from mixture A and put into mixture B, then what will be the ratio of liquid X to liquid Y in mixture B? Correct Answer 85 : 59

CALCULATION:

The total quantity of liquid Y = 40 liters

Let the quantity of liquid X in mixture A be a liters

Quantity of liquid X in mixture B = a + 10

so,

a + a + 10 + 40 = 40 + 60

2a = 50

a = 25 liters

Quantity of liquid X in mixture A = 25 liters

Quantity of liquid X in mixture B = 25 + 10 = 35 liters

Quantity of liquid Y in mixture A = 40 - 25 = 15 liters

Quantity of liquid Y in mixture B = 60 - 35 = 25 liters

Required ratio = 35 + 30% of 25 : 25 + 30% of 15

⇒ 42.5 : 29.5 = 85 : 59 

∴ The answer will be 85 : 59

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