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A container has a mixture of liquids A and B. The ratio of liquids A to B is 4 : 5. How much mixture must be taken out of the container and replaced with liquid A so that the final mixture should contain liquids A and B in ratio 1 : 1?

A container has a mixture of liquids A and B. The ratio of liquids A to B is 4 : 5. How much mixture must be taken out of the container and replaced with liquid A so that the final mixture should contain liquids A and B in ratio 1 : 1? Correct Answer 0.9

Let the initial mixture be of 9 litres

∴ Amount of A and B is 4 and 5 litres respectively

If ‘x’ litres are taken out, 4x/9 and 5x/9 are the amounts of A and B taken out

∴ Amount of A and B left will be (4 – 4x/9 + x) and (5 - 5x/9)

∴ According to the given conditions,

⇒ (4 + 5x/9)/(5 - 5x/9) = 1 : 1

⇒ 4 + 5x/9 = 5 – 5x/9

∴ 10x/9 = 1

∴ x = 0.9

∴ 0.9 litres of mixture must be taken out

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