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Two containers A and B have concentration of water and milk such that A contains 40% and B contains 14% water respectively. Some part of mixture in container A is replaced by equal quantity of mixture from container B. How much quantity of the mixture was replaced if final mixture contains 68% milk?

Two containers A and B have concentration of water and milk such that A contains 40% and B contains 14% water respectively. Some part of mixture in container A is replaced by equal quantity of mixture from container B. How much quantity of the mixture was replaced if final mixture contains 68% milk? Correct Answer 9 : 13

Given: Two containers A and B have concentration of water and milk such that A contains 40% and B contains 50% water respectively. Some part of mixture in container A is replaced by equal quantity of mixture from container B.

Formula:

Ratio of water = 9 ∶ 4

So, replaced part = 9/(9 + 4) = 9 ∶ 13

∴ The replaced part is 9 ∶ 13

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