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Two vessels A and B contain mixture of alcohol and water such that A contains 25% alcohol and B contains 15% alcohol. Some part of mixture in vessel A is replaced by equal quantity of mixture from vessel B. How much quantity of the mixture was replaced if final mixture vessel 18% alcohol?

Two vessels A and B contain mixture of alcohol and water such that A contains 25% alcohol and B contains 15% alcohol. Some part of mixture in vessel A is replaced by equal quantity of mixture from vessel B. How much quantity of the mixture was replaced if final mixture vessel 18% alcohol? Correct Answer 7/10

Given:

Quantity of alcohol in vessel A = 25%

Quantity of alcohol in vessel B = 15%

Quantity of alcohol in mixture = 18%

Concept used:

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Calculations:

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So, ratio is 3 ∶ 7

So, Replaced part = 7 ∶ 10

∴ Quantity of the mixture was replaced in 7 ∶ 10

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