In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: A milk-water mixture contained 20% water. How much milk must be added to 160 litres of the mixture, so that the final mixture contains only 10% water? Quantity B: An alcohol-water mixture is prepared by mixing alcohol and water in the ratio 1 ∶ 6. How much mixture can be prepared using 22 litres of alcohol?
In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: A milk-water mixture contained 20% water. How much milk must be added to 160 litres of the mixture, so that the final mixture contains only 10% water? Quantity B: An alcohol-water mixture is prepared by mixing alcohol and water in the ratio 1 ∶ 6. How much mixture can be prepared using 22 litres of alcohol? Correct Answer Quantity A > Quantity B
Solving for Quantity A:
Quantity of water in 160 litres of mixture = 20% of 160 = 1/5 × 160 = 32 litres
Now, the quantity of water in final mixture remains the same
⇒ 32 = 10% of Quantity of final mixture = 1/10 × Quantity of final mixture
⇒ Quantity of final mixture = 32 × 10 = 320 litres
⇒ Quantity of milk to be added = 320 – 160 = 160 litres
⇒ Quantity A = 160 litres
Solving for Quantity B:
Ratio of mixture = 1 ∶ 6
Sum of ratios = 1 + 6 = 7
⇒ Quantity of alcohol in mixture = 1/7 × Total quantity of mixture
⇒ 22 = 1/7 × Total quantity of mixture
⇒ Total quantity of mixture = 22 × 7 = 154 litres
⇒ Quantity B = 154 litres
∴ Quantity A > Quantity B