A person has 3 containers (cylindrical, spherical, and hemispherical) full of water. The radius of each container is equal and the height of the cylindrical container is 14 m. If the volume of the cylindrical container is 396 m3 and water from all three containers is put in the big cuboidal container whose length and breadth is 20 m and 12 m. How much water rises in a cuboidal container?
A person has 3 containers (cylindrical, spherical, and hemispherical) full of water. The radius of each container is equal and the height of the cylindrical container is 14 m. If the volume of the cylindrical container is 396 m3 and water from all three containers is put in the big cuboidal container whose length and breadth is 20 m and 12 m. How much water rises in a cuboidal container? Correct Answer 33/14 m
Given:
Radius of cylinder, sphere, and hemisphere is equal
Height of cylindrical vessel = 14 m
Volume of cylindrical vessel = 396 m3
Formula used:
Volume of cylinder = πr2h
Volume of sphere = 4/3 π r3
Volume of hemisphere = 2/3 π r3
Calculation:
Volume of the cylinder = π × R2 × H
⇒ 396 = (22/7) × R2 × 14
⇒ R2 = (396 × 7)/ (14 × 22)
⇒ R = 3 m
Radius of each container = 3 m
Total volume of water in all three container = volume of water in the cuboidal container
Volume of cylinder + volume of sphere + volume of hemisphere = l × b × h
⇒ π × 3 × 3 × 14 + (4/3) × π × 3 × 3 × 3 + (2/3) × π × 3 × 3 × 3 = 20 × 12 × h
⇒ 9π (14 + 4 +2) = 20 × 12 × h
⇒ 9π = 12 × h
⇒ h = 33/14
∴ Water rise in cuboidal container = 33/14 m