How many atoms of hydrogen are liberated at cathode , when 965 coulombs of charge is passed through water ?
How many atoms of hydrogen are liberated at cathode , when 965 coulombs of charge is passed through water ?
A. `6.02 xx 10^(21)`
B. `6.02 xx 10^(23)`
C. `6.02 xx 10^(-19)`
D. `6.02 xx 10^(19)`
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Correct Answer - A
`H_(2)O to H_(2) + (1)/(2) O_(2) or 2 H^(+) + 2e^(-) to 2H` i.e., 96500 C produce 1 mole H-atoms = `6.02 xx 10^(23)` atoms . So 965 C will produce H-atoms = `6.02 xx 10^(21)`.
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