How many moles of platinum will be deposited on the cathode when 0.60 F of electricity is passed through a 1.0 M solution of `Pt^(4+)` ?
How many moles of platinum will be deposited on the cathode when 0.60 F of electricity is passed through a 1.0 M solution of `Pt^(4+)` ?
A. 0.60 mol
B. 0.15 mol
C. 0.30 mol
D. 0.45 mol
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Correct Answer - B
`Pt^(4+)(aq)+underset(0.6F)underset(4F)4e^(-) to underset(((1mol)xx(0.6F))/((4F))=0.15" mol")underset(1" mol")(Cu(s))`
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