Two faradays of electricity are passed through a solution of `CuSO_(4)`.The mass of copper deposited at the cathode is (atomic mass of Cu=63.5 g)

Question

Two faradays of electricity are passed through a solution of `CuSO_(4)`.The mass of copper deposited at the cathode is (atomic mass of Cu=63.5 g)

Two faradays of electricity are passed through a solution of `CuSO_(4)`.The mass of copper deposited at the cathode is (atomic mass of Cu=63.5 g)
A. 2 g
B. 127 g
C. 0 g
D. 63.5 g

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
(d) The reduction reaction is :
`Cu^(2+)(aq)+underset(2F)2e^-) to underset(=63.5 g)underset(1 g" atom")(Cu(s))`

5 views Answered 2023-02-05 15:29