If 0.5 amp current is passed through acidified silver nitrate solution for 100 minutes the mass of silver deposited on cathode, is (eq. wt. of silver
If 0.5 amp current is passed through acidified silver nitrate solution for 100 minutes the mass of silver deposited on cathode, is (eq. wt. of silver nitrate=108) :
A. 2.3523 g
B. 3.3575 g
C. 5.3578 g
D. 6.3575 g
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Correct Answer - B
(b) Current (I) =0.5 amp.
Time (t)=100 mm
`=100xx60 sec.=6000 s`.
Eq. mass of Ag (E ) =108
`W=(EIt)/(96500)=(108xx0.5xx6000)/(96500)=3.3575 g`.
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