In the electrolysis of an aqueous solution of `NaOH`, `2.8` litres of `O_(2)(g)` is liberated at the anode at `NTP`. Volume of hydrogen gas liberated
In the electrolysis of an aqueous solution of `NaOH`, `2.8` litres of `O_(2)(g)` is liberated at the anode at `NTP`. Volume of hydrogen gas liberated at the cathode at `NTP` will be
A. `5.6`
B. `6.5`
C. `22.2`
D. `11.2`
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Correct Answer - A
96500 or 1 F will liberate 1 eq. of `O_(2) = 22.4 dm^(3)`
(Lit) or 1/4 mole `O_(2)` or 5.6 litre `O_(2)` at NTP .
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