A closed pipe has certain frequency. Now its length is halved. Considering the end correction, its frequency will now become
A. Double
B. More than double
C. Less than double
D. Four time

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1 Answers

Correct Answer - C
`n_1 = (v)/(4(l+e))`
and `n_2 = (v)/(4(l/2+e))= (2v)/(4(l+2e))`
Thus `n_2` is less than double of `n_1`

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