A closed pipe has certain frequency. Now its length is halved. Considering the end correction, its frequency will now become
A closed pipe has certain frequency. Now its length is halved. Considering the end correction, its frequency will now become
A. Double
B. More than double
C. Less than double
D. Four time
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Correct Answer - C
`n_1 = (v)/(4(l+e))`
and `n_2 = (v)/(4(l/2+e))= (2v)/(4(l+2e))`
Thus `n_2` is less than double of `n_1`
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