The frequency of the first overtons of a closed pipe of length `l_(1)` is equal to that of the first overtone of an open pipe of length `l_(2)` The ra

Question

The frequency of the first overtons of a closed pipe of length `l_(1)` is equal to that of the first overtone of an open pipe of length `l_(2)` The ra

The frequency of the first overtons of a closed pipe of
length `l_(1)` is equal to that of the first overtone of an
open pipe of length `l_(2)` The ratio of their lengths `(l_(1) : l_(2)` is
A. `2 : 3`
B. `4 : 5`
C. `3 : 5`
D. ` 3 : 4`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - d
Here, `v_(1)=((2n-1))/(4l_(1))v and v_(2) = n/(2l_(2))=v`
Hence, ` v_(1)=v_(2)`
`therefore (2n-1)/(4l_(1))=n/(2l_(2))`
`therefore l_(1)/l_(2)=(2n-1)/(2n)`(where n=2)
The ratio of lengths `l_(1)/l_(2)=3/4`

6 views Answered 2023-02-05 15:29