If a JFET with length L=10µm, a=2µm, W=8µm, Vp=-4V.What is the value of rds at Vgs = 0V?
If a JFET with length L=10µm, a=2µm, W=8µm, Vp=-4V.What is the value of rds at Vgs = 0V? Correct Answer 9.8KΩ
rds=L/(2aqND µnW) = Nd = 2V/qa2=1.33×1021 atoms/m3 µn=0.15m2/v-sec On substituting the values, we get rds=9.8KΩ.