The difference between `Delta H` and `Delta E` (on a molar basis) for the combustion of n-octane `(l)` at `25^(@)C` would be:

Question

The difference between `Delta H` and `Delta E` (on a molar basis) for the combustion of n-octane `(l)` at `25^(@)C` would be:

The difference between `Delta H` and `Delta E` (on a molar basis) for the combustion of n-octane `(l)` at `25^(@)C` would be:
A. `13.6 kJ`
B. `-1.14 kJ`
C. `-11.15 kJ`
D. `+11.15 kJ`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`C_(8)H_(18)(l)+(25)/(2)O_(2)(g)rarr8CO_(2)(g)+9H_(2)O(l)`
`Delta n_(g)=8-(25)/(2)=(16-25)/(2)= -(9)/(2)= -4.5`
`Delta H-Delta E= Delta_(g)RT= -(4.5xx8.314xx298)/(1000)= -11.15 kJ`

5 views Answered 2023-02-05 15:29