The approxiamte standard enthalpies of formation of methanol and octane are determiend to be -1.5 kJ/mol and -10.9 kJ/mol respectively. The standard e
The approxiamte standard enthalpies of formation of methanol and octane are determiend to be -1.5 kJ/mol and -10.9 kJ/mol respectively. The standard enthalpies of combustion of octane is denoted as `DeltaH("octane")` and that fo methanol as `DeltaH` (methanol). the correct statement is:
A. `DeltaH` (octane) is more negative than `DeltaH` (methanol)
B. `DeltaH`(octane) is less negative than `DeltaH` (methanol)
C. `DeltaH` (octane) is equal to `DeltaH` (methanol)
D. `DeltaH` (octane)`+DeltaH`(methanol)=0
6 views
1 Answers
Correct Answer - A
Heat of combustion of octane will be more negative than methanol because octane has greaterr number of carbon than methanol.
6 views
Answered