On mixing, heptane and octane form an ideal solution. At 373 K. The vapour pressure of the two luquid components (heptane and octane) are 105 kPa and

Question

On mixing, heptane and octane form an ideal solution. At 373 K. The vapour pressure of the two luquid components (heptane and octane) are 105 kPa and

On mixing, heptane and octane form an ideal solution. At 373 K. The vapour pressure of the two luquid components (heptane and octane) are 105 kPa and 45 kPa repectively. Vapour pressure of the solution obtained by mixing 25.0 g of heptane and 35 g of octane will be (molar mass of heptane= 100 g `mol^(-1)` and of octane= 114 g `mol^(-1)`)
A. 144.5 kPa
B. 72.0 kPa
C. 36.1 kPa
D. 96.2 kPa

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - b
`n_("ethanol")=((25g))/((100mol^(-1)))=0.25 "mol"`
` X_("octane")=((35g))/((114 g mol^(-1)))=0.30 "mol"`
`X_("heptane")=(0.25)/(0.25+0.30)=0.45`
`"Xoctane"=(0.30)/(0,25+0.30)=0.55`
`P=(0.45xx105 "K pa")xx(0.55xx45"K pr")`
`=47.25+24.75=72 "K pa"`.

4 views Answered 2023-02-05 15:29