10 g of neon initinally at a pressure of 506.625 kPa and temperature of 473 K expand adiabatically to a pressure of 202.65 kPa . Calculate entropy of

Question

10 g of neon initinally at a pressure of 506.625 kPa and temperature of 473 K expand adiabatically to a pressure of 202.65 kPa . Calculate entropy of

10 g of neon initinally at a pressure of 506.625 kPa and temperature of 473 K expand adiabatically to a
pressure of 202.65 kPa . Calculate entropy of the system and of total entropy change for the following
ways of carrying out is this expamsion .
(i) Expansion is carried out expansion .
(ii) Expansion occurs aganist a constant external pressure of 202.65 kPa .
(iii) Expansion is a free expansion.

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - (i) `DeltaS_("sys") = 0; DeltaS_("surr")= 0 and DeltaS_("total")= 0`, (ii) `DeltaS_("surr")= 0; DeltaS_("total")= DeltaS_("sys") = 0.957 JK^(-1)` (iii) `DeltaS_("sys") = DeltaS_("total")= 3.81 JK^(-1)`
(i) For reversible adiabatic process
`DeltaS_(surr)= 0" "DeltaS_(sure)= - DeltaS_(system) = 0`
`DeltaS_("total") = DeltaS _(sys)+DeltaS = 0 `
Hence `DeltaS_(sys)= DeltaS_(surr)= DeltaS_("total") =0`
(ii) `DeltaS_(surr)= 0`
`DeltaS_(sys)= nC_(V)In ((T_(2))/(T_(1)))+ nR In ((V_(2))/(V_(1)))`
`= nC_(V) In ((T_(2))/(T_(1))) + nR In ((P_(1))/(P_(2))(T_(1))/(T_(2)))`
`= n[C_(V) In ((T_(2))/(T_(1))) + nR In ((T_(2))/(T_(1)))+ In((P_(1))/(P_(2)))]`
`= n[C_(V) In ((T_(2))/(T_(1))) + nR In((P_(1))/(P_(2)))]" "[T_(2)" of irreverrsubile adiabatic will be calculated "]`
`= 0.957 J//K" "by w = DeltaU rArr - P_(ext)(V_(2)-V_(1))=nC_(V,m)(T_(1)-T_(2))`