`1` mole of an ideal gas at `25^(@)` C is subjected to expand reversibly and adiabatically to ten times of its initial volume. Calculate the change in

Question

`1` mole of an ideal gas at `25^(@)` C is subjected to expand reversibly and adiabatically to ten times of its initial volume. Calculate the change in

`1` mole of an ideal gas at `25^(@)` C is subjected to expand reversibly and adiabatically to ten times of its initial volume. Calculate the change in entropy during expansion (in `J K^(-1) mol^(-1)`)
A. `19.15`
B. `-19.15`
C. `4.7`
D. zero

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`DeltaS = nC_(v) l"n" (T_(2))/(T_(1)) + nR l"n" (V_(2))/(V_(1))`
For adiabatic process `(Q-0)`
`DeltaE = W " " implies" "nC_(v) ln(T_(2))/(T_(1)) =-nR ln (V_(2))/(V_(1)) " " therefore" "DeltaS=0`

5 views Answered 2023-02-05 15:29