On mixing , heptate and octane form an ideal solution. At 373 K. The vapour pressure of the two liquid components (heptaane and octane) are 105 kPa an

Question

On mixing , heptate and octane form an ideal solution. At 373 K. The vapour pressure of the two liquid components (heptaane and octane) are 105 kPa an

On mixing , heptate and octane form an ideal solution. At 373 K. The vapour pressure of the two liquid components (heptaane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtainde by mixing 25.0 g of heptane and 35 g of octane will be (molar mass of heptane=100 g `mol^(-1)` )
A. 0.0186 K
B. 0.0372 K
C. 0.0558 K
D. 0.0744 K

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - c
Fro `NaSO4, i=3`
Since `alpha` is eaual to 1
`"Molality (m)"=((0.01mol))/(1kg)`
`DeltaT_(f)=ixxK_(f)xxm`
`=3xx(1.86 " K kg"mol^(-1)) xx (0.01 mol kg^(-1))`
=0.0558 K.

4 views Answered 2023-02-05 15:29