Heat of combustion of ethanol at constant pressure and at temperature T K(=298 K) is found to be -qJ `"mol"^(-1)`. Hence , heat of combustion (in J `"
Heat of combustion of ethanol at constant pressure and at temperature T K(=298 K) is found to be -qJ `"mol"^(-1)`. Hence , heat of combustion (in J `"mol"^(-1)`) of ehtanol at the same temperature at constant volume will be:
A. RT-q
B. `-(q+RT)`
C. q-RT
D. q+RT
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Correct Answer - A
`C_(2)H_(5)OH(l) + 3O_(2)(g) rarr 3H_(2)O(r)`
`Deltan_(3)=2-3=-1`
so `DeltaU=DeltaH-Deltan_(g)RT`
`=-q+RT`
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