A ball is projected to attain the maximum range. If the height attained is H, the range is
A. H
B. 2H
C. 4H
D. H/2

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1 Answers

Correct Answer - C
Maximum range for a given velocity is attained at `theta=45^(@)`
`R_("max")=(u^(2)sin2theta)/(g)rArrR_("max")=(u^(2)sin90^(@))/(g)=(u^(2))/(g)`
`therefore R_("max")=4.H_("max")`

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