A particle is projected with `20ms^(-1)` at `30^(@)` above horizontal. Find ratio of maximum height to the range of the projectile.
A. `(1)/(4sqrt(3))`
B. `sqrt(3)/(4)`
C. `4sqrt(3)`
D. `(4)/sqrt(3)`

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1 Answers

`H=(u^(2)sin^(2)theta)/(2g)`
`R=(v^(2)s2intheta)/(g)`
`(H)/(R)-(tan theta)/(4)`

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