1 mole of `FeSO_(4)` (Atomic mass of `Fe = 55.84g mol^(-1)`) is oxidised to `Fe_(2)(SO_(4))_(3)`. The equivlent mass of `Fe^(2+)` ions is:

Question

1 mole of `FeSO_(4)` (Atomic mass of `Fe = 55.84g mol^(-1)`) is oxidised to `Fe_(2)(SO_(4))_(3)`. The equivlent mass of `Fe^(2+)` ions is:

1 mole of `FeSO_(4)` (Atomic mass of `Fe = 55.84g mol^(-1)`) is oxidised to `Fe_(2)(SO_(4))_(3)`. The equivlent mass of `Fe^(2+)` ions is:
A. 55.84
B. 27.92
C. 83.76
D. 111.68

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`overset(+2)(2FeSO_(4)) to overset(+3)(2Fe_(2))(SO_(4))_(3)`
Change in oxidation state per Fe atom =1
`:.` Equivalent mass = Atomic mass =55.84 g `"equiv"^(-1)`

4 views Answered 2023-02-05 15:29