If `3*01xx10^(20)` molecules are removed from 98 mg of `H_(2)SO_(4)`, then the number of moles of `H_(2)SO_(4)` left are

Question

If `3*01xx10^(20)` molecules are removed from 98 mg of `H_(2)SO_(4)`, then the number of moles of `H_(2)SO_(4)` left are

If `3*01xx10^(20)` molecules are removed from 98 mg of `H_(2)SO_(4)`, then the number of moles of `H_(2)SO_(4)` left are
A. `0*1xx10^(-3)`
B. `0*5xx10^(-3)`
C. `1*66xx10^(-3)`
D. `9*95xx10^(-2)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Moles of `H_(2)SO_(4)` removed
`= (3*01xx10^(20))/(6*02xx10^(23))=0*5xx10^(-3)`
Total moles of `H_(2)SO_(4) = (98xx10^(-3))/(98) = 1xx10^(-3)`
Moles of `H_(2)SO_(4)` left
`=1xx10^(-3)-0*5xx10^(-3)`
`=0*5xx10^(-3)` moles

4 views Answered 2023-02-05 15:29