In the DNA of E. Coli the mole ratio of adenine to cytosine is `0.7`. If the number of moles of adenine in the DNA is 350000, the number of moles of g
In the DNA of E. Coli the mole ratio of adenine to cytosine is `0.7`. If the number of moles of adenine in the DNA is 350000, the number of moles of guanine is equal to -
A. `350000`
B. `500000`
C. `225000`
D. `700000`
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Correct Answer - B
`(A)/(C)=0.7`
`(35xx10^(4))/(0.7)=0.7`
`C=(35xx10^(4))/(0.7)=5xx10^(5)`
Moles of cytosine = moles of guanine
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