In an n-p-n transistor, the current gain for common emitter configuration is 80. If the emitter current be 8.1 mA, then the base current will be

Question

In an n-p-n transistor, the current gain for common emitter configuration is 80. If the emitter current be 8.1 mA, then the base current will be

In an n-p-n transistor, the current gain for common emitter configuration is 80. If the emitter current be 8.1 mA, then the base current will be
A. 0.1 `mu A`
B. `0.01 muA`
C. `0.1 muA`
D. `0.01 mA`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`beta=800, I_(e)=8.1 mA, I_(b)= ? `
`beta=(I_(c))/(I_(b))=(I_(e)-I_(b))/(I_(b))`
`betaI_(b)=I_(e)-I_(b)`
`I_(b)=(I_(e))/(beta+1)=(8.1)/(81)=0.1 mA`

4 views Answered 2023-02-05 15:29