A galvanometer of resistance `100Omega` gives full scale deflection for the current of 0.1 A . The series resistance required to convert it into voltmeter of range 100 V is
A. `800Omega`
B. `900Omega`
C. `700Omega`
D. `600Omega`

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1 Answers

Correct Answer - B
`R=(V)/(I_g)-G=(100)/(0.1)-100=900Omega` .

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