A galvanometer of resistance `100Omega` gives full deffection for a current `10^(-5)` the value of shunt required to convert it into ammeter of range 1 ampere is:-
A. `10^-3Omega` in series
B. `100Omega` in parallel
C. `100 Omega` in series
D. `10^-3` in parallel

5 views

1 Answers

Correct Answer - D
`I=((S+G)/(S))l_(g)=((2+40)/(2))xx0.01=0.21A`

5 views

Related Questions