The resistance of 1 A ammeter is `0.018 Omega` . To convert it into 10 A ammeter, the shunt resistance required will be

Question

The resistance of 1 A ammeter is `0.018 Omega` . To convert it into 10 A ammeter, the shunt resistance required will be

The resistance of 1 A ammeter is `0.018 Omega` . To convert it into 10 A ammeter, the shunt resistance required will be
A. `0.2 Omega`
B. `0.02 Omega`
C. `0.002Omega`
D. `0.001Omega`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

A galvanometer of resistance `15 Omega` gives full scale deflection for a current of 2mA. Calculate the shunt resistance needed to convert it into an

2 Answers 4 Views

यदि `omega` इकाई का घनमूल है और हो `A=[{:(,1,1,1),(,1,omega,omega^(2)),(,1,omega^(2),omega):}]`, तो दर्शाइए की `A^(-1)=1/3 [{:(,1,1,1),(,1,omega^(2),o

2 Answers 5 Views

A galvanometer of resistance `100Omega` gives full deffection for a current `10^(-5)` the value of shunt required to convert it into ammeter of range

2 Answers 5 Views

Resistance of galvanometer is `500Omega`. Effective resistance of ammeter with shunt is `25 Omega`. What is the value of shunt ?

2 Answers 4 Views

An ammeter is obtained by shunting a `30 Omega` galvanometer with a `30 Omega` resistance. What additional shunt should be connected across it to doub

2 Answers 4 Views

What resistance should be connected in series with a 0.5 A ammeter to convert it into a 15 V voltmeter ? Given that the resistance of ammeter.

2 Answers 11 Views

A moving coil galvanometer is converted into an ammeter reads upto `0.03 A` by connecting a shunt of resistance `4r` across it and ammeter reads up `0

2 Answers 4 Views

A galvanometer having a resistance of `75 Omega` gives the full scale deflection for the current of 25mA. The shunt required to convert it into an amm

2 Answers 4 Views

The combined resistance of a galvanometer of resistance of `495` ohm and its shunt is `9.9 Omega` . The shunt resistance is

2 Answers 4 Views

To convert a 400 m V range galvanometer of resistance `20 Omega` into a ammeter of 100 m A ranges , the required shunt resistance to be connected is

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`S=((I_g)/(I-I_g))G=((0.050)/(3-0.05))xx118=2Omega`

5 views Answered 2023-02-05 15:29