A moving coil galvanometer is converted into an ammeter reads upto `0.03 A` by connecting a shunt of resistance `4r` across it and ammeter reads up `0
A moving coil galvanometer is converted into an ammeter reads upto `0.03 A` by connecting a shunt of resistance `4r` across it and ammeter reads up `0.06 A`, when a shunt of resistance `r` is used. What is the maximum current which can be sent through this galvanometer if no shunt is used ?
A. `0.01A`
B. `0.02A`
C. `0.03A`
D. `0.04A`
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Correct Answer - B
`I_(g)=((S_1)/(S_1+G))I=((S_2)/(S_2+G))`
From this `G=2r`.
`I_(g) = (4r)/(4r+2r)xx0.03=0.02A`.
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