An ammeter is obtained by shunting a `30 Omega` galvanometer with a `30 Omega` resistance. What additional shunt should be connected across it to double the range ?
A. `10 Omega`
B. `15 Omega`
C. `30 Omega`
D. none of these

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1 Answers

Correct Answer - B
Let x be the total number of divisions.
`therefore I_g= x//60 and I=x//10`
`therefore S=((I_g)/(I-I_g))G=[(((x)/(60)))/(((x)/(10)-(x)/(60)))]20=4Omega`

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