A galvanometer having a resistance of `75 Omega` gives the full scale deflection for the current of 25mA. The shunt required to convert it into an ammeter to measure the current up to 59 A is
A. `0.017Omega`
B. `0.047Omega`
C. `0.027Omega`
D. `0.037Omega`

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1 Answers

Correct Answer - D
`S=((I_g)/(I-I_g))G=(25xx10^-3)/((50-0.025))xx75=0.0375 Omega`

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