A moving coil galvanometer hs a resistance of 25 `omega` and gives a full scale deflection for a current of 10 mA how will you convert it in to voltem
A moving coil galvanometer hs a resistance of 25 `omega` and gives a full scale deflection for a current of 10 mA how will you convert it in to voltemeter having range 0-100 V ?
A. `9.975 k Omega` in series
B. `8.965 kOmega` in series
C. `10.343 kOmega` in series
D. `6.638 kOmega` in series
1 Answers
Given resistance of galvanometer `G= 25 omega`
current througjh gavnometer `I_(g) =10 mA`
`=10xx10^(-3)A=10^(-2)A`
voltmeter reading V=100 V
series resistance R= ?
MCG is converted into voltmeter by coinnecting high resistance `(R_(G))` in series with it which is given by
`R=(V)/(I_(g))-G`
`R=(100)/(10^(-2))-25 =10000-25`
`R=9975 omega` in series
`=9.975 k omega` in series