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A galvanometer has a resistance `100Omega` and gives a full scale deflection for a current of 0.1 A. It is to be converted into a voltmeter of range of 50 V. The resistance of voltmeter so formed is
A. `400 Omega`
B. `500 Omega`
C. `200Omega`
D. `80 Omega`

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1 Answers

Correct Answer - B
`(F_m)/(F_e)=(v^2)/(c^2)=((3xx10^5)^2)/((3xx10^8)^2)=10^-4`.

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