A sinusoidal voltage of amplitude 5V is applied to resistance of `500 Omega`. The r.m.s. current in the circuit is

Question

A sinusoidal voltage of amplitude 5V is applied to resistance of `500 Omega`. The r.m.s. current in the circuit is

A sinusoidal voltage of amplitude 5V is applied to resistance of `500 Omega`. The r.m.s. current in the circuit is
A. A. `5/(sqrt(2)) mA`
B. B. `10/(sqrt(2)) mA`
C. C. `10sqrt(2) mA`
D. D. `20sqrt(2) mA`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

Given the resistances of `1 Omega, 2 Omega, 3 Omega` how will be combine them to get an equivalent resistance of (i) (11/3) `Omega` (ii) (11/5) `Omega

2 Answers 4 Views

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which `R = 3 Omega. L = 25.48mH`. And `C = 796mu F`

2 Answers 5 Views

A sinusoidal carrier wave of amplitude 40 V is amplitude modulated by a sinusoidal signal voltage. What is the amplitude of each side band if the modu

2 Answers 5 Views

यदि `omega` इकाई का घनमूल है और हो `A=[{:(,1,1,1),(,1,omega,omega^(2)),(,1,omega^(2),omega):}]`, तो दर्शाइए की `A^(-1)=1/3 [{:(,1,1,1),(,1,omega^(2),o

2 Answers 5 Views

In series LCR circuit `R = 18 Omega` and impedence is `33 Omega`. An Vrms voltage `220 V` is applied across the circuit . The true power consumed in A

2 Answers 6 Views

A sinusoidal carrier voltage of 120 V is amplitude modulated by a sinusoidal voltage of frequency 10KHz. What is the modulation index if the maximum m

2 Answers 5 Views

When a sinusoidal carrier wave of voltage amplitude 3 kV is amplitude modulated by a sinusoidal signal voltage, two side bands each of amplitude 600 V

2 Answers 6 Views

A sinusoidal voltage is used to amplitude modulate a sinusoidal voltage of amplitude 1 KV. This results in the production of two side bands, each of a

2 Answers 5 Views

A common emitter amplifier has current gain 70. Its load resistance is 5 `k Omega` and input resistance is 500 `Omega` . The voltage gain is

2 Answers 6 Views

The voltage over a cycle varies as `V=V_(0)sin omega t` for `0 le t le (pi)/(omega)` `=-V_(0)sin omega t` for `(pi)/(omega)le t le (2pi)/(omega)` The

2 Answers 11 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`I_(0)=5/500 = 1/100 A = 10 mA :. I_(rms) = 10/(sqrt2) mA`.

4 views Answered 2023-02-05 15:29