In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g
In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. Find out the percentage of bromine in the compound.
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Mass of the substance taken=0.15g
Mass of AgBr= 0.12g
1 mole of AgBr=1 g atom of Br
188g of AgBr = 80 g of Br
0.12 g of AgBr contain bromine= 80/188*0.12
But this much amount of bromine is present in 0.15g of the organic compound
Therefore, percentage of bromine= 80*0.12*100/188*0.15
= 34.04
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