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A man walked 8 km towards South from his house. Then he turned right and walked 4 km. He again turned right and walked 4 km. He again turned right and walked 8 km. Thereafter, he turned right and walked 6 km. Approximately how far was he from the starting point?

A man walked 8 km towards South from his house. Then he turned right and walked 4 km. He again turned right and walked 4 km. He again turned right and walked 8 km. Thereafter, he turned right and walked 6 km. Approximately how far was he from the starting point? Correct Answer 11 km

Let O is starting point and A, B, C, D and E is point in diagram where he passes through,

[ alt="Reporte" src="//storage.googleapis.com/tb-img/production/17/07/Reporte.png" style="height:297px; width:324px">

We can see that EX = OA = 8 + 2 = 10 Km, XO = 4 Km

Hence distance between starting and ending point is = (OX2+XE2)1/2

(102+42)1/2= (100+16)1/2= (116)1/2 = 10.77 = 11 Km

Hence distance between starting and ending point is 11 km.

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