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After starting from his house, Naren walked a few meters towards the east. From there, he took a right turn and walked 80 m, and then took a left turn and walked 20m. Finally, he took a right turn again and walked 40 m to reach the hospital. If the air distance between his house and the hospital is 130m, how far did Naren walk towards the east initially?

After starting from his house, Naren walked a few meters towards the east. From there, he took a right turn and walked 80 m, and then took a left turn and walked 20m. Finally, he took a right turn again and walked 40 m to reach the hospital. If the air distance between his house and the hospital is 130m, how far did Naren walk towards the east initially? Correct Answer 30 m

According to given information,

[ alt="SSC COP Paper 1 D1" src="//storage.googleapis.com/tb-img/production/19/11/SSC%20COP%20Paper%201_D1.PNG">

Let A denote Naren’s house and B denote the hospital.

OB = 80 + 40 = 120 m.

By Pythagoras’ theorem,

AB2 = OA2 + OB2.

Therefore, OA2 = 1302 - 1202 =2500 and OA = 50 m.

Thus, the required answer = 50 - 20 = 30 m.

Hence, the correct answer is 30 m.

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