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A potentiometer R5 is put in the apex of the bridge shown in the figure to balance the circuit. If Ru = 500 Ω; Rv = 500 Ω; R2 = 515 Ω; R3 = 480 Ω; and R5 = 100 Ω, then find the values of R6 and R7­ to balance the bridge and compensate for the unequal values of R2 and R3.

A potentiometer R5 is put in the apex of the bridge shown in the figure to balance the circuit. If Ru = 500 Ω; Rv = 500 Ω; R2 = 515 Ω; R3 = 480 Ω; and R5 = 100 Ω, then find the values of R6 and R7­ to balance the bridge and compensate for the unequal values of R2 and R3. Correct Answer R<sub>6</sub> = 67.5 Ω and R<sub>7</sub> = 32.5 Ω

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Ru = 500 Ω, Rv = 500 Ω, R2 = 515 Ω, R3 = 480Ω, R5 = 100Ω

We know that R5 = R6 + R7 ⇒ R6 + R7 = 100      …..(1)

After balancing the bridge, we get

Ru (R7 + R2) = Rv (R3 + R6)

For a balanced bridge product of impedance of opposite arms should be equal.

∴ 500(R7 + 515) = 500 (480 + R6)

R7 + 35 = R6­      …..(2)

Solving the equations (1) and (2) we get,

R7 = 32.5 Ω and R6 = 67.5 Ω

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