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The following table shows the daily seats occupancy in different classes of a train. Numbers in the bracket represent the total seats available for a particular class. Day 2nd Class Non-AC (900) 1st Class Non-AC (500) AC III Tier (500) AC II Tier (250) AC 1st Class (150) Monday 850 460 480 240 145 Tuesday 840 400 450 230 120 Wednesday 830 390 480 220 130 Thursday 790 480 490 250 125 Friday 840 470 500 210 130 What is the ratio of number of seats that remained vacant in all the Non-AC classes on Wednesday and Thursday taken together to number of seats remained vacant in AC classes on Monday, Tuesday and Friday?

The following table shows the daily seats occupancy in different classes of a train. Numbers in the bracket represent the total seats available for a particular class. Day 2nd Class Non-AC (900) 1st Class Non-AC (500) AC III Tier (500) AC II Tier (250) AC 1st Class (150) Monday 850 460 480 240 145 Tuesday 840 400 450 230 120 Wednesday 830 390 480 220 130 Thursday 790 480 490 250 125 Friday 840 470 500 210 130 What is the ratio of number of seats that remained vacant in all the Non-AC classes on Wednesday and Thursday taken together to number of seats remained vacant in AC classes on Monday, Tuesday and Friday? Correct Answer 62 <span style="">∶ 39</span>

Calculation:

The number of seat remained vacant in 2nd class Non-AC on Wednesday = (900 – 830) = 70

The number of seat remained vacant in 2nd class Non-AC on Thursday = (900 – 790) = 110

The number of seat remained vacant in 1st class Non-AC on Wednesday = (500 – 390) = 110

The number of seat remained vacant in 1st class Non-AC on Thursday = (500 – 480) = 20

Total number of vacant seat in all the Non-AC classes on Wednesday and Thursday = (70 + 110 + 110 + 20)

⇒ 310

The number of seat remained vacant in AC III tier on Monday = (500 – 480) = 20

The number of seat remained vacant in AC III tier on Tuesday = (500 – 450) = 50

The number of seat remained vacant in AC II tier on Monday = (250 – 240) = 10

The number of seat remained vacant in AC II tier on Tuesday = (250 – 230) = 20

The number of seat remained vacant in AC II tier on Friday = (250 – 210) = 40

The number of seat remained vacant in AC 1st class on Monday = (150 – 145) = 5

The number of seat remained vacant in AC 1st class on Tuesday = (150 – 120) = 30

The number of seat remained vacant in AC 1st class on Friday = (150 – 130) = 20

Total number of vacant seat in all the AC classes on Monday, Tuesday and Friday = (20 + 50 + 10 + 20 + 40 + 5 + 30 + 20)

⇒ 195

The ratio of number of seats that remained vacant in all the Non-AC classes on Wednesday and Thursday taken together to number of seats remained vacant in AC classes on Monday, Tuesday and Friday = (310 : 195)

⇒ 62 : 39

∴ The required ratio is 62 : 39

Related Questions

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