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The following table shows day-wise number of seats occupied of different classes in a train. Numbers in bracket represent the total seats available in a particular class. Day 2nd Class Non-AC (900) 1st Class Non-AC (500) AC III Tier (500) AC II Tier (250) AC 1st Class (150) Monday 850 460 480 240 145 Tuesday 840 400 450 230 120 Wednesday 830 390 480 220 130 Thursday 790 480 490 250 125 Friday 840 470 500 210 130 How many seats remained vacant taking all the days together in non-AC classes?

The following table shows day-wise number of seats occupied of different classes in a train. Numbers in bracket represent the total seats available in a particular class. Day 2nd Class Non-AC (900) 1st Class Non-AC (500) AC III Tier (500) AC II Tier (250) AC 1st Class (150) Monday 850 460 480 240 145 Tuesday 840 400 450 230 120 Wednesday 830 390 480 220 130 Thursday 790 480 490 250 125 Friday 840 470 500 210 130 How many seats remained vacant taking all the days together in non-AC classes? Correct Answer 650

Calculation:

No of vacant seats in 2nd non-AC class & 1st class non-AC class on Monday = (900 - 850) + (500 - 460) = 90

No of vacant seats in 2nd non-AC class & 1st class non-AC class on Tuesday = (900 - 840) + (500 - 400) = 160

No of vacant seats in 2nd non-AC class & 1st class non-AC class on Wednesday = (900 - 830) + (500 - 390) = 180

No of vacant seats in 2nd non-AC class & 1st class non-AC class on Thursday = (900 - 790) + (500 - 480) = 130

No of vacant seats in 2nd non-AC class & 1st class non-AC class on Monday = (900 - 840) + (500 - 470) = 90

∴ No of seats remained vacant taking all the days together in non-AC classes = 90 + 160 + 180 + 130 + 90 

⇒ 650

Related Questions

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